Respuesta :

[tex]\tan x=4 \Rightarrow \tan(\pi +x)=4[/tex]

because

[tex]\tan x= \tan (x+n\pi),\, n\in\mathbb{Z}[/tex]

The value of the periodic triogonometric function which is tan (π + x) using the value of tan x = 4 gives us; tan (π + x) = 4

How to solve periodic trigonometric functions?

We are given the trigonometric function;

tan(x) = 4

Now, we want to find tan(π + x).

Now, tan (π + x) is periodic and as such we can say that;

tan x = tan (x + nπ)

Where n belongs to a set of all integers. Thus, we can conclude that;

tan (π + x) = tan x = 4

Read more about Trigonometric Periodic Functions at; https://brainly.com/question/6904750