the origin is (0,0)
so it is 5 units left from orogin and 12 units down
if we were to start from the origin, and draw a line that is 5 units long to the left, then draw a line that is 12 units down from that point, then connect the end point to the origin we get a triangle
legs are legnth 12 and 5
hypotonuse=?
12^2+5^2=?^2
144+25=?^2
169=?^2
sqrt both sides
13=?
answer is 13 units
or use distance fomrula
which is overkill
distance between ponts (x1,y1) and (x2,y2) is
D=[tex] \sqrt{(x2-x1)^{2}+(y2-y1)^{2}} [/tex]
in this case, between (0,0) and (-5,-12)
D=[tex] \sqrt{(-5-0)^{2}+(-12-0)^{2}} [/tex]
D=[tex] \sqrt{(-5)^{2}+(-12)^{2}} [/tex]
D=[tex] \sqrt{25+144} [/tex]
D=[tex] \sqrt{169} [/tex]
D=13
asnswer is 13 units (distance is always positive)
