Hello!
Solve the following system of equations by the substitution method.
5x = y + 6
2x - 3y = 4
What is the value of the y-coordinate?
-8/13
13/14
14/13
Solving:
5x = y + 6 (I)
2x - 3y = 4 (II)
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We have:
[tex]5x = y + 6 \to x = \dfrac{y+6}{5}[/tex]
Soon:
[tex]2x - 3y = 4[/tex]
[tex]2* \left(\dfrac{y+6}{5}\right) - 3y = 4[/tex]
[tex]\dfrac{2y+12}{5} - 3y = 4[/tex]
least common multiple (5)
[tex]\dfrac{2y+12}{5} - 3y = 4\to \dfrac{2y+12}{\diagup\!\!\!\!\!5} - \dfrac{15y}{\diagup\!\!\!\!\!5} = \dfrac{20}{\diagup\!\!\!\!\!5}[/tex]
[tex]2y + 12 - 15y = 20[/tex]
[tex]- 15y + 2y = 20 - 12[/tex]
[tex]- 13\:y = 8[/tex]
[tex]\boxed{\boxed{y = - \dfrac{8}{13} }}\end{array}}\qquad\quad\checkmark[/tex]
Answer:
- 8/13
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I Hope this helps, greetings ... Dexteright02! =)
