Respuesta :
a)
y = mx + c
y = 1x + 3
y = x + 3
b)
y = 2x ? 5 comparing to y = mx + c, slope = m
slope = 2.
But for a perpendicular line, we take the negative reciprocal,
= -1/2 = -1/2
y = mx + c
y = 1x + 3
y = x + 3
b)
y = 2x ? 5 comparing to y = mx + c, slope = m
slope = 2.
But for a perpendicular line, we take the negative reciprocal,
= -1/2 = -1/2
Answer:
1) The equation of the line whose y-intercept is 3 and slope is 1 is given by [tex]y=x+3[/tex]
2) The slope of a line perpendicular to the line whose equation is [tex]y=2x+5[/tex] is [tex]-\frac{1}{2}[/tex]
Step-by-step explanation:
1) To find : What is the equation of the line whose y-intercept is 3 and slope is 1?
Solution :
The general slope form of the line is [tex]y=mx+c[/tex]
Where, m is the slope m=1
and c is the y-intercept c=3
Substitute in the equation of line,
[tex]y=(1)x+3[/tex]
[tex]y=x+3[/tex]
Therefore, The equation of the line whose y-intercept is 3 and slope is 1 is given by [tex]y=x+3[/tex]
2) To find : What is the slope of a line perpendicular to the line whose equation is [tex]y = 2x+5[/tex]?
Solution :
When two lines are perpendicular the slope of one equation is negative reciprocal of another slope of equation.
The slope of given equation is 2.
The negative reciprocal is [tex]-\frac{1}{2}[/tex]
Therefore, The slope of a line perpendicular to the line whose equation is [tex]y=2x+5[/tex] is [tex]-\frac{1}{2}[/tex]