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d = {x|x is a whole number} e = {x|x is a perfect square between 1 and 9} f = {x|x is an even number greater than or equal to 2 and less than 9} which of the following is d ∩ f? a. {4, 6} b. {2, 4, 6} c. {2, 4, 6, 8} d. {2}

Respuesta :

dalendrk
[tex]D=\{0;\ 1;\ 2;\ 3;\ 4;...\}\\E=\{4\}\\F=\{2;\ 4;\ 6;\ 8\}\\\\D\ \cap\ F=\{2;\ 4;\ 6;\ 8\}=F\to\boxed{c.}\\conclusion\ F\subset D[/tex]

Answer:

Correct option is:

c. {2, 4, 6, 8}

Step-by-step explanation:

d = {x|x is a whole number}

i.e. d={0,1,2,3,...}

f = {x|x is an even number greater than or equal to 2 and less than 9}

i.e. f={2,4,6,8}

Intersection(∩) of two sets gives the element which is common in both the sets

d∩f={0,1,2,3,...}∩{2,4,6,8}

     = {2,4,6,8}

Hence, Correct option is:

c. {2, 4, 6, 8}

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