Respuesta :
m = 150 kg.
Final velocity, v = 14 m/s
Initial Velocity, u = 6 m/s
Impulse = m(v - u)
= 150*(14 - 6)
= 150*8 = 1200 kgm/s or 1200 Ns
Final velocity, v = 14 m/s
Initial Velocity, u = 6 m/s
Impulse = m(v - u)
= 150*(14 - 6)
= 150*8 = 1200 kgm/s or 1200 Ns
Answer: The magnitude of impulse acted on the cart will be 1200 kg.m/s
Explanation:
Impulse is defined as the product of mass of the object and the change in its velocity. It is basically the change in momentum of the body.
Mathematically,
[tex]J=m\Delta v[/tex]
where,
J = Impulse
m = mass of the object
[tex]\Delta v=v_2-v_1[/tex] = change in the velocity
We are given:
[tex]m=150kg\\v_1=6m/s\\v_2=14m/s\\J=?kg.m/s[/tex]
Putting values in above equation, we get:
[tex]J=150kg\times (14-6)m/s=1200kg.m/s[/tex]
Hence, the magnitude of impulse acted on the cart will be 1200 kg.m/s