Answer: The product would be [tex]d^{j+k}[/tex]
Step-by-step explanation:
Since we have given that
[tex]d^j.d^k[/tex]
We need to find the product.
As we know that
[tex]a^m\times a^n=a^{m+n}[/tex]
So, we will use the above exponential law and it becomes,
[tex]d^j.d^k=d^{j+k}[/tex]
Hence, the product would be [tex]d^{j+k}[/tex]
