Respuesta :
[tex]x=10\ and\ x=2\ are\ zeros\ of\ the\ function\\\\(x-10)(x-2)=x^2-2x-10x+20=x^2-12x+20\\\\a)\ f(x)=x^2-12x+20\to\boxed{YES}\\\\b)\ f(x)=x^2-20x+12\to\boxed{NOT}\\\\c)\ f(x)=5x^2+40x+60=5(x^2+8x+12)\to\boxed{NOT}\\\\d)\ f(x)=5x^2+60x+100=5(x^2+12x+20)\to\boxed{NOT}[/tex]