contestada

A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.

Respuesta :

Molar mass :

[tex]H_2SO_4= 1*2+32+16*4= 98g/mol[/tex]

Number of moles:

[tex]n = \frac{solute}{molar( mass)} [/tex]

[tex]n = \frac{73.5g}{98g/mol} [/tex]

[tex]n=0.75 (moles)[/tex]

Volume = 3.0 L

[tex]M = \frac{n}{V} [/tex]

[tex]M = \frac{0.75(moles)}{3.0L} [/tex]

[tex]M = 0.25 mol/L ^{-1} [/tex]

hope this helps!