The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens to the pressure
of the gas?
It decreases by a factor of four.
It increases by a factor of four.
It decreases by a factor of eight.
It increases by a factor of eight.

Respuesta :

Answer:

It increases by a factor of four.

Explanation:

To answer this question, we can use the pressure's law, which states that:

"For a constant mass of an ideal gas kept at constant volume, the pressure of the gas is directly proportional to the absolute temperature of the gas"

Mathematically:

[tex]\frac{p}{T}=const.[/tex]

where

p is the pressure of the gas

T is its absolute temperature

The equation can be rewritten as

[tex]\frac{p_1}{T_1}=\frac{p_2}{T_2}[/tex]

In this problem we have:

[tex]T_2=4T_1[/tex], since the absolute temperature of the gas is increased by 4 times

Here we want to find p2; solving for it, we find:

[tex]p_2=\frac{T_2}{T_1}p_1 = \frac{4T_1}{T_1}p_1 = 4p_1[/tex]

So, the pressure

It increases by a factor of four.

nutboi

Answer:

increases factor pressure by four

Explanation: