Answer:
D. 10.91 square centimeters
Step-by-step explanation:
Area of a sector of a circle = [tex]\frac{\theta}{360}\\[/tex] [tex]\pi[/tex][tex]r^{2}[/tex]
where [tex]\theta = 50^{o} C[/tex]
radius (r) = half of diameter = 10/2 = 5 cm
Area = [tex]\frac{50}{360} * \frac{22}{7} * 5^{2}[/tex]
= 10.91 [tex]cm^{2}[/tex]
The area of this sector is 10.91 square centimeters
The region of a disk enclosed by two radii and an arc is called a circular sector, also known as a circle sector or disk sector. The smaller area is referred to as the minor sector, and the larger area as the major sector.
The formula for the area of the sector of a circle is /360* (r2) where r is the radius of the circle and is the angle of the sector.
Given
d = 10
r = 5
= 50
a = 50/360 * 3.14 * 5 * 5 = 10.91
Therefore, The area of this sector is 10.91 square centimeters
To know more about area of a sector of a circle refer to :
https://brainly.com/question/9406374
#SPJ2
