Respuesta :
Answer:
Answer is
Base of triangle is 14 cm
Height of a triangle is 56 cm
Step-by-step explanation:
[tex]Given \: area \: of \: a \: triangle \: = 392 \: sq.cm \\ given \: height \: of \: a \: triangle \: is \: 4 \: times \\ the \: base \: . \: (h = 4b) \\ area \: of \: a \: triangle = \frac{1}{2} \times b \times h \\ on \: substituting \: the \: above \: \\ mentioned \\ datas \: in \: the \: formula \\ 392 = \frac{1}{2} \times b \times 4b \\ 392 = \frac{1}{2} \times 4 {b}^{2} \\ multiply \: by \: 2 \: on \: both \: sides \: \\ we \: get \\ 2 \times 392 = 4 {b}^{2} \\ 4 {b}^{2} = 784 \\ {b}^{2} = \frac{784}{4 } \\ {b }^{2} = 196 \\ b = 14 \: cm\\ h = 4b \\ h = 4 \times 14 \\ h = 56 \: cm[/tex]
HAVE A NICE DAY!
THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION.
Answer:
Area of triangle, a=392[Given]
Let the base of triangle be x and height be 4x.
According to question:-
[tex]Area \: of \: triangle = \frac{1}{2} \times base \times height[/tex]
[tex]392 = \frac{1}{2} \times x \times4x[/tex]
[tex]392 = \frac{1}{2} \times 4x {}^{2} [/tex]
[tex]392 \times 2 = 4x {}^{2} [/tex]
[tex]784 = 4x {}^{2} [/tex]
[tex]x {}^{2} = \cancel \frac{784}{4} [/tex]
[tex]x {}^{2} = 196[/tex]
[tex]x = \sqrt{196} [/tex]
