Given:
x = 12 in, y = 16 in and z = 20 in
To find:
The surface area of the geometric shape.
Solution:
Area of top rectangle = z × z
= 20 × 20
Area of top rectangle = 400 in²
Area of middle rectangle = z × y
= 20 × 16
Area of middle rectangle = 320 in²
Area of bottom rectangle = z × x
= 20 × 12
Area of bottom rectangle = 240 in²
Area of left triangle = [tex]\frac{1}{2}yx[/tex]
[tex]$=\frac{1}{2}\times16\times12[/tex]
Area of left triangle = 96 in²
Area of right triangle = [tex]\frac{1}{2}yx[/tex]
[tex]$=\frac{1}{2}\times16\times12[/tex]
Area of right triangle = 96 in²
Surface area = 400 + 320 + 240 + 96 + 96
= 1152
The surface area of the geometric shape is 1152 in².
