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What is the molar solubility of calcium carbonate ( CaCO3 ) in water? The solubility-product constant for CaCO3 is 4.5 × 10-9 at 25 °C.
A) 8.35
B) 9.5 × 10-5
C) 9.0 × 10-9
D) 2.3 × 10-9
E) 6.7 × 10-5

Respuesta :

Edufirst

Answer:

Option E)

  • [tex]6.7\times 10^{-5}M[/tex]

Explanation:

1. Write the solubility equation:

  • CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻

2. Write the concentrations below the equation:

  • CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻

             A - s               s            s

3. Write the Ksp equation:

  • Ksp = [Ca²⁺] . [CO₃²⁻]       ↔ the solid substances do not appear
  • Ksp = s × s
  • 4.5 × 10⁻⁹ = s²

4. Solve the equation:

       [tex]s=\sqrt{4.5\times 10^{-9}M^2}=6.7\times 10^{-5}M[/tex]

E) 6.7 × 10-5 is the answer.

Ksp Equation

Ksp = [ Ca^2+]*[Co3^2-]

Ksp = s*s

405*10^-9 = s^2

s =[tex]\sqrt 4.5*10^{-9} * M ^{2}[/tex]

6.7 × 10-5 M

How is molar solubility calculated?

Ksp is a feature of temperature. Say that the Ksp for AgCl is 1.7 x 10-10. With these records, you may discover the molar solubility which is the number of moles that can be dissolved in line with liter solution until the answer turns saturated. The devices are given in moles according to L, in any other case known as mol/L or M.

Solubility indicates the most amount of a substance that may be dissolved in a solvent at a given temperature. This kind of solution is called saturated. Divide the mass of the compound through the mass of the solvent after which multiply by 100 g to calculate the solubility in g/100g.

Ksp (Solubility product regular) is the equilibrium among a strong and its respective ions in a solution. The cost of the constant identifies the degree to which the compound can dissociate in water. For an instance the higher the Ksp the greater soluble the compound is.

Learn more about molar solubility here: https://brainly.com/question/16027456

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