Answer:
Distance covered by B is 4 times distance covered by A
Explanation:
For an object in free fall starting from rest, the distance covered by the object in a time t is
[tex]s=\frac{1}{2}gt^2[/tex]
where
s is the distance covered
g is the acceleration due to gravity
t is the time elapsed
In this problem:
- Object A falls through a distance [tex]s_A[/tex] during a time t, so the distance covered by object A is
[tex]s_A=\frac{1}{2}gt^2[/tex]
- Object B falls through a distance [tex]s_B[/tex] during a time 2t, so the distance covered by object B is
[tex]s_B=\frac{1}{2}g(2t)^2 = 4(\frac{1}{2}gt^2)=4s_A[/tex]
So, the distance covered by object B is 4 times the distance covered by object A.
