Answer:
Step-by-step explanation:
hello :
let :
y : the length , x : the width , A : the area, x and y positifs numbers (y>x)
you have the system : xy=180....(*)
y=x+8...(**)
put the value for y by (**) in to(*) : (x+8)x=180
x²+8x-180 =0......a=1 b=8 c = -180
∆ = b²- 4ac
∆ = 8²- 4(1)(-180)=384=28²
X1 = ( -b - √∆)/2a = (-8-28)/2 = -15 refused
X2= ( -b + √∆)/2a = (-8+28)/2 = 10
x=10 but : y=x+8
y = 10+8 =18
The length of the rectangle is...18...cm.
The width of the rectangle is...10...cm.