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A cylinder of argon gas contains 50.0 L of Ar at 18.4 atm and 127 °C. How many moles of argon is in the cylinder?

Respuesta :

Answer:

n=28.03

Explanation:

For this problem you would have to use the Ideal gas law formula which is [tex]PV=nRT[/tex]. In this formula, R is called the ideal gas law constant which is R= 0.08205

For your problem, this formula would look like this...[tex]n=\frac{PV}{RT}[/tex]

First you would have to convert Celsius to Kelvin:   273 + 127 C= 400K

Your problem would look like this in the formula [tex]n= \frac{(18.4 atm)(50.0 L)}{(0.08205)(400 K)}[/tex]

Once solved n= 28.03 mol