The answer for the following problem is mentioned below.
The option for the question is "A" approximately.
Explanation:
Given:
Spring constant (k) = 240 N/m
amount of the compression (x) = 0.40 m
To calculate:
Elastic potential energy (E)
We know;
According to the formula;
E = [tex]\frac{1}{2}[/tex] × k × x × x
E = [tex]\frac{1}{2}[/tex] × k ×(x)²
where;
E represents the elastic potential energy
K represents the spring constant
x represents amount of the compression in the string
So therefore,
Substituting the values in the above formula;
E = [tex]\frac{1}{2}[/tex] × 240 × (0.40)²
E = [tex]\frac{1}{2}[/tex] × 240 × 0.16
E = [tex]\frac{1}{2}[/tex] × 38.4
E = 19.2 J or approximately 20 J
Therefore the elastic potential energy of the string is 20 J.