Answer:
[tex]a_{5}[/tex] = [tex]\frac{7}{8}[/tex]
Step-by-step explanation:
The n th term of a geometric sequence is
[tex]a_{n}[/tex] = a[tex](r)^{n-1}[/tex]
where a is the first term and r the common ratio
Here a = 14 and r = [tex]\frac{-7}{14}[/tex] = - [tex]\frac{1}{2}[/tex], thus
[tex]a_{5}[/tex] = 14 × [tex](-\frac{1}{2}) ^{4}[/tex] = 14 × [tex]\frac{1}{16}[/tex] = [tex]\frac{14}{16}[/tex] = [tex]\frac{7}{8}[/tex]
