Solve (x-3)^2 = 5 HELP ASAP!!! Please!! :(
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Answer:
Answer is option d
Step-by-step explanation:
[tex]given \: expression \: is \: {(x - 3)}^{2} = 5 \\ {x}^{2} - 6x + 9 = 5 \\ subtracting \: 5 \: on \: both \: sides \: we \: get \\ {x}^{2} - 6x + 4 = 0 \\ on \: solving \: the \: quadratic \: equation \: by \\ \: completing \: square \: method \\ {x}^{2} - 6x = - 4 \\ adding \: {3}^{2} on \: both \: sides \: w e\: get \\ {x}^{2} - 6x + {3}^{2} = {3}^{2} - 4 \\ {(x - 3)}^{2} = 5 \\ x - 3 + = \sqrt{5} \\ x = \sqrt{5 } + 3[/tex]
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