A club began with 3 members. Each month, each member brought one new member. Which function can be used to determine the number of members x months after the club began? A. f(x) = 2x + 3 B. f(x) = 3x + 1 C. f(x) = 1.5(2)x D. f(x) = 3(2)x

Respuesta :

In x th month, members =  [tex]3^{2x}[/tex]. Option D.

Step-by-step explanation:

Given,

Initially number of members = 3

Every month each member brought 1 new member.

To find the number of members after x months.

Solution:

In 1st month, members = 3

In 2nd month, members = 3×3 = 9 = 3²

In 3rd month, members = 9×9 = 81 = [tex]3^{4}[/tex]

In 4th month, members = 81×81 = 81 = 6561 = [tex]3^{8}[/tex]

Hence,

In x th month, members =  [tex]3^{2x}[/tex]

Answer:

D

Step-by-step explanation:

The starting number is 3

And they bring in 1 member each month

That can be shown with the last equation

Good luck!