Answer:
-4 chickens.
-8 beef plates
Step-by-step explanation:
Let x denote a chicken dish and y denote a beef dish.
-Assume that every member only had one dish of either chicken or beef.
#The problem is then represented as:
[tex]x+y=12, =>x=12-y\ \ \ \ \ \ ...i\\\\10x+14y=136\ \ \ \ \ \ \ \ \ ...ii\\\\\#substitute \\10(12-y)+14y=136\\\\120-10y+14y=136\\\\2y=16\\\\y=8\\\\\therefore x=12-8=4[/tex]
Hence, the memebers had a total of 4 chicken dishes and 8 beef dishes