Answer:
The answer to your question is 37.5 l of water vapor
Explanation:
Data
volume of ethane = 12.5 l
volume of water vapor = ?
Balanced chemical reaction
2C₂H₆ + 7O₂ ⇒ 4CO₂ + 6H₂O
-Convert the volume of C₂H₂ to moles
1 mol of C₂H₂ --------------- 22.4 l
x --------------- 12.5 l
x = (12.5 x 1) / 22.4
x = 0.56 moles
-Calculate the moles of water vapor
2 moles of C₂H₂ --------------- 6 moles of H₂O
0.56 moles of C₂H₂ ---------- x
x = (0.56 x 6) / 2
x = 1.67 moles of H₂O
-Calculate the volume of water vapor
22.4 l of H₂O ----------------- 1 mol
x ----------------- 1.67 moles
x = (1.67 x 22.4) / 1
x = 37.5 l
