The secants intersect outside the circle . Therefore, the secant length(segment SV) is 16 units
If a secant and a tangent intersect outside a circle, the product of one secant segment and it external segment is equal to the product of the other secant segment and it external segment
Therefore,
VW × VS = VU × VT
6(y + 4 + 6) = 8(y - 2 + 8)
Hence,
6(y + 10) = 8(y + 6)
6y + 60 = 8y + 48
6y - 8y = 48 - 60
-2y = - 12
divide both sides by -2
y = -12 / -2
y = 6
Therefore,
SV = y + 4 + 6 = 6 + 6 + 4 = 16 units
learn more on secant intersection here:https://brainly.com/question/12115042
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