Which of the following electron configurations represents an excited state of the indicated atom? Group of answer choices

a.Na: 1s2 2s2 2p6 3s2 3p2 3s1
b.Ne: 1s2 2s2 2p6
c.N: 1s2 2s2 2p3
d.P: 1s2 2s2 2p6 3s2 3p2 4s1
e.He: 1s2

Respuesta :

Answer: The electronic configuration of the atom that represents excited state is P: [tex]1s^22s^22p^63s^23p^24s^1[/tex]

Explanation:

There are 2 states classified under energy levels:

  1. Ground state: This is the lower energy state which is termed as stable state.
  2. Excited state: This is the upper energy state and is termed as the unstable state. All the electrons which are present in this state always come back to the ground state.

For the given options:

  • For a: Sodium

The atomic number of sodium element is 11. The ground state electronic configuration of this element is [tex]1s^22s^22p^63s^1[/tex]

  • For b: Neon

The atomic number of neon element is 10. The ground state electronic configuration of this element is [tex]1s^22s^22p^6[/tex]

  • For c: Nitrogen

The atomic number of nitrogen element is 7. The ground state electronic configuration of this element is [tex]1s^22s^22p^3[/tex]

  • For d: Phosphorus

The atomic number of phosphorus element is 15. The ground state electronic configuration of this element is [tex]1s^22s^22p^63s^23p^3[/tex]

One electron from the valence shell jumps into outer shell and the excited state electronic configuration becomes [tex]1s^22s^22p^63s^23p^24s^1[/tex]

  • For e: Helium

The atomic number of helium element is 2. The ground state electronic configuration of this element is [tex]1s^2[/tex]

Hence, the electronic configuration of the atom that represents excited state is P: [tex]1s^22s^22p^63s^23p^24s^1[/tex]