The temperature at which the volume of the gas will be 0.55 L if it had a volume of 0.432 L is 49.1 °C
Charles' law
Charles' law states as follow:
V₁ / T₁ = V₂ / T₂
Where
- V₁ is the initial volume
- T₁ is the initial temperature
- V₂ is the new volume
- T₂ is the new temperature
How to determine the new volume
From the question given above, the following data were obtained
- Initial volume (V₁) = 0.432 L
- Initial temperature (T₁) = –20 °C = –20 + 273 = 253 K
- New Volume (V₂) = 0.55 L
- New temperature (T₂) = ?
V₁ / T₁ = V₂ / T₂
0.432 / 253 = 0.55 / T₂
Cross multiply
0.432 × T₂ = 253 × 0.55
Divide both side by 0.432
T₂ = (253 × 0.55) / 0.432
T₂ = 322.1 K
Subtract 273 from 332.1 to express in degree Celsius (°C)
T₂ = 322.1 – 273
T₂ = 49.1 °C
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