Answer:
The maximum efficiency the plant will ever achieve is 75%
Explanation:
From the question given, we recall the following:
Th flames in the boiler reaches a temperature of = 1200K
the cooling water is = 300K
The maximum efficiency the plant will achieve is defined as:
Let nmax = 1 - Tmin /Tmax
Where,
Tmin = Minimum Temperature in plants
Tmax = Maximum Temperature in plants
The temperature of the cooling water = Tmin = 300K
The temperature of the flames in boiler = Tmax = 1200k=K
The maximum efficiency becomes:
nmax = 1 - Tmin /Tmax
nmax = 1 - 300 /1200
nmax = 1-1/4 =0.75
nmax = 75%
