Consider the triangle below.
Find the perimeter of triangle ABC. Round to the nearest hundredth.

A) 18.86 units
B) 120 units
C) 13.47 units
D) 6.43 units

Consider the triangle below Find the perimeter of triangle ABC Round to the nearest hundredth A 1886 units B 120 units C 1347 units D 643 units class=

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Answer:

Option A is correct.

Step-by-step explanation:

[tex]\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\[/tex]

Using the above mentioned distance formula, we have:

[tex]\mathrm{Distance\:between\:}\left(1,\:3\right)\mathrm{\:and\:}\left(3,\:-2\right):\quad \sqrt{29}\:\:\:\mathrm{or}\:\:5.39\:\\\\\\\mathrm{Distance\:between\:}\left(1,\:3\right)\mathrm{\:and\:}\left(-4,\:-1\right):\quad \sqrt{41}\:\:\:\mathrm{or}\:\:6.4\:\\\\\\\mathrm{Distance\:between\:}\left(3,\:-2\right)\mathrm{\:and\:}\left(-4,\:-1\right):\quad 5\sqrt{2}\:\:\:\mathrm{or}\:\:7.07\:\\\\[/tex]

Add the length of three sides of triangles, we have:

Perimeter = 5.39+6.4+7.07 = 18.86