Respuesta :
Answer:
Step-by-step explanation:
[tex]\frac{5+x}{25-x^2} >0\\=\frac{5+x}{(5+x)(5-x)} \\=\frac{1}{5-x} >0\\if~5-x>0\\or~5>x\\or x<5[/tex]
The nonnegative value of x is the expression will be x > 5.
What is an asymptote?
An asymptote is a line that constantly reaches a given curve but does not touch at an infinite distance.
Making anything easier to accomplish or comprehend, as well as making it less difficult, is the definition of simplification.
The expression is given below.
⇒ (5 + x) / (25 - x²)
Simplify the expression, then the expression will be
⇒ (5 + x) / (25 - x²)
⇒ (5 + x) / (5² - x²)
⇒ (5 + x) / [(5 - x)(5 + x)]
⇒ 1/(5 - x)
We know that the denominator should be greater than zero for a positive value.
If the value of the expression (5 - x) is greater than 0, then we have
5 - x > 0
x > 5
The nonnegative value of x is the expression will be x > 5.
More about the asymptote link is given below.
https://brainly.com/question/17767511
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