At a party, you use a gas canister to fill balloons. The canister holds 4.47 moles of air. If the room is at 26.0°C and the gas
pressure is 855 kilopascals, what is the volume of the canister?
Type the correct answer in the box. Express your answer to the correct number of significant figures C. Use the gas laws
fact sheet to help you.
The volume of the canister is _____
liters.

Respuesta :

Answer: 13.0

Explanation: First rearrange the ideal gas law equation to isolate V: (V=nRT/p) Next, concert the temperature to kelvins. Use the formula (K = °C + 273.15) so (K= 26°C + 273.15 = 299.15 K) For the gas constant, use: R = 8.314(L kPa/mol K) because the pressure is given in kilopascal. Substitute the values and simplify: V = [4.47 mol x 8.314 (L kPa/mol K) x 299.15 K] / 855 kPa = 13.0 liters

The canister holds 4.47 moles of air, the room is at 26.0°C and the gas pressure is 855 kilopascals, then the volume is 13 liters.

How do we calculate volume?

Volume of any gas will be calculated by using an ideal gas equation is:

PV = nRT, where

P = pressure of canister = 855 kPa

V = volume of canister = ?

R = universal gas constant = 8.314 L.kPa/mol K

n = moles of air in canister = 4.47 mol

T = temperature of room = 26.0°C = 299.15K

On putting value, we get

V = (4.47)(8.314)(299.15) / (855)

V = 13 L

Hence required volume of canister is 13 liters.

To know more about ideal gas equation, visit the below link:
https://brainly.com/question/24236411