Respuesta :
Answer: 13.0
Explanation: First rearrange the ideal gas law equation to isolate V: (V=nRT/p) Next, concert the temperature to kelvins. Use the formula (K = °C + 273.15) so (K= 26°C + 273.15 = 299.15 K) For the gas constant, use: R = 8.314(L kPa/mol K) because the pressure is given in kilopascal. Substitute the values and simplify: V = [4.47 mol x 8.314 (L kPa/mol K) x 299.15 K] / 855 kPa = 13.0 liters
The canister holds 4.47 moles of air, the room is at 26.0°C and the gas pressure is 855 kilopascals, then the volume is 13 liters.
How do we calculate volume?
Volume of any gas will be calculated by using an ideal gas equation is:
PV = nRT, where
P = pressure of canister = 855 kPa
V = volume of canister = ?
R = universal gas constant = 8.314 L.kPa/mol K
n = moles of air in canister = 4.47 mol
T = temperature of room = 26.0°C = 299.15K
On putting value, we get
V = (4.47)(8.314)(299.15) / (855)
V = 13 L
Hence required volume of canister is 13 liters.
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https://brainly.com/question/24236411