A particular deep-sea fish has a swim bladder that can hold a maximum to 0.34 L of gas. It lives at 500m depth. If the fish's swim bladder currently holds 0.12 L of gas, about how high could researchers safely raise it before rupturing ("popping") the swim bladder? (Show your work)

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Answer:

At the height of the 176 meter fish's swim bladder will hold the gas without rupturing its swim badder, at this height researchers can safely raise it.

Explanation:

Pressure at depth of  500 m = [tex]p_1=\rho\times g\times 500 m[/tex]

Volume of gas hold by fish's swim bladder = [tex]V_1=0.12 L[/tex]

Pressure at dept h where fish's swim bladder can hold maximum gas = [tex]P_2=\rho\times g\times h[/tex]

Maximum volume of the gas in fish's swim bladder = [tex]V_2=0.34 L[/tex]

Applying Boyle's law:

[tex]P_1V_1=P_2V_2[/tex]  ( at constant temperature)

[tex]\rho\times g\times 500 m\times 0.12 L=\rho\times g\times h\times 0.34 L[/tex]

[tex]h=\frac{\rho\times g\times 500 m\times 0.12 L}{\rho\times g\times 0.34 L}=176.5 m\approx 176 m[/tex]

At the height of the 176 meter fish's swim bladder will hold the gas without rupturing its swim badder, at this height researchers can safely raise it.