Answer:
The answer to your question is V2 = 0.92 l
Explanation:
Data
Volume 1 = V1 = 2.4 l
Pressure 1 = P1 = 1.5 atm
Temperature 1 = T1 = 273 °C
Volume 2 = V2 = ?
Pressure 2 = 4.5 atm
Temperature 2 = 313 °K
Process
To solve this problem use the Combined gas law
P1V1/T1 = P2V2/T2
-Solve for V2
V2 = P1V1T2 / T1P2
-Substitution
V2 = (1.5 x 2.4 x 313) / (273 x 4.5)
-Simplification
V2 = 1126.8 / 1228.5
-Result
V2 = 0.92 l
