Respuesta :
The minimum of a quadratic function, with a positive coefficient a, is its vertex.
Let's find the x₀ coordinate.
[tex]f(x) = 5x^2 -70x + 258\\\\x_0=\dfrac{-b}{2a}=\frac{-(-70)}{2*5} =\frac{70}{10} =7[/tex]
Now we need to find y₀ coordinate. That will be the minimum of function.
[tex] y_0=5\times7^2-70\times7+258=13[/tex]
So, the minimum cost to produce the product is $13
Decompose 5x^2 − 70x + 258 into multipliers
[tex]5x^2 - 70x + 258=(5x^2-70x+245)+13=5(x^2-14+49)+13=\\=5(x-7)^2+13[/tex]
Answer: 5(x − 7)^2 + 13; The minimum cost to produce the product is $13.
Answer:
5(x − 7)2 + 13; The minimum cost to produce the product is $13.
Step-by-step explanation:
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