How do you solve for the Rations of Special Triangles? This is confusing
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Answer:
The answer to your question is x = [tex]\frac{3\sqrt{2}}{2}[/tex]
Step-by-step explanation:
Data
right triangle
x = ?
hypotenuse = 3
To solve this problem use trigonometric functions. The trigonometric function that relates the opposite side and the hypotenuse is sine.
sin Ф = Opposite side / hypotenuse
-Solve for Opposite side (x)
x = hypotenuse sin 45
-Substitution
sin 45 = [tex]\frac{\sqrt{2}}{2}[/tex]
x = 3[tex]\frac{\sqrt{2}}{2}[/tex]
-Solution
x = [tex]\frac{3\sqrt{2}}{2}[/tex] It is not possible to simplify any more.