Answer:
Kc = 208 for 3H₂(g) + N₂(g) ⇄ 2NH₃(g)
Explanation:
3H₂(g) + N₂(g) ⇄ 2NH₃(g)
C(i) 0.20mol/L 0.10mol/L 0.00mol/L
ΔC -3x -x +2x
C(eq) (0.20-3x)M (0.10-x)M 0.080M
= 0.20-3(0.04)M =(0.10-0.04)M
= 0.080M = 0.060M
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*2x = 0.080M => x = (0.080/2)M = 0.040M
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Kc = [NH₃]²/[H₂]³[N₂] = (0.080)²/(0.080)³(0.060) = 208
