Answer:
[tex]\huge\boxed{3y^2+12y=3y(y+4)}[/tex]
Step-by-step explanation:
[tex]3y^2=(3)(y)(y)\\\\12y=(3)(2)(2)(y)\\\\\text{Gratest Common Factor:}\ GCF(3y^2,\ 12y)=(3)(y)=3y\\\\3y^2+1y=(3y)(y)+(3y)(4)\\\\\text{Use the distributive property:}\ a(b+c)=ab+ac\\\\3y^2+12y=(3y)(y+4)[/tex]
Answer:
3y(y + 4).
Step-by-step explanation:
3y^2 + 12y
We first need to find the Greatest Common Factor of the 2 terms:
The GCF of 3 and 12 is 3.
The GCF of y^2 and y = y.
So the required GCF is 3y.
Now we divide the expression by 3y to get the factors. The quotient goes into the parentheses:
(3y^2 + 12y) / 3y = y + 4 so the factors are:
3y(y + 4).
