Answer:
A) f(x) = (x + 0)^2 − 9 and f(x) has a minimum value f(0) = −9
Step-by-step explanation:
The given factored form is the factorization of the difference of squares. When multiplied out, it becomes ...
f(x) = x^2 -9
which can be written as ...
f(x) = (x -0)^2 -9
Compared to vertex form ...
f(x) = a(x -h)^2 +k
we find the vertex (h, k) to be (0, -9), and the scale factor a to be 1. The positive scale factor means the parabola opens upward, and the vertex represents a minimum.
f(x) has a minimum at f(0) = -9.