Answer:
[tex]\huge\boxed{\dfrac{6}{7}+\dfrac{3}{5}=\dfrac{51}{35}=1\dfrac{16}{35}}[/tex]
Step-by-step explanation:
[tex]\dfrac{6}{7}+\dfrac{3}{5}\\\\\text{Find the}\ LCD-\text{Least Common Denominator}\\\\\text{List multiples of 7}:\ 0,\ 7,\ 14,\ 21,\ 28,\ \boxed{35},\ 42,\ ...\\\text{List multiples of 5:}\ 0,\ 5,\ 10,\ 15,\ 20,\ 25,\ 30,\ \boxed{35},\ 40,\ ...\\\\LCD(7,\ 5)=\boxed{35}\\\\35=7\cdot5[/tex]
[tex]\dfrac{6}{7}+\dfrac{3}{5}=\dfrac{(6)(5)}{(7)(5)}+\dfrac{(7)(3)}{(7)(5)}=\dfrac{30}{35}+\dfrac{21}{35}=\dfrac{30+21}{35}=\dfrac{51}{35}=\dfrac{35+16}{35}=1\dfrac{16}{35}[/tex]
