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A horizontal force accelerates a cart of mass 200 kg from 0 to 30 m/s on a horizontal
smooth surface. If the horizontal distance the force acts over is 12 m, what is the
magnitude of the force?

Respuesta :

Chelboy

Answer:7500 newton

Explanation:

mass(m)=200kg

Initial velocity(u)=0

Final velocity(v)=30m/s

Distance(d)=12m

Acceleration=a

V^2=u^2+2 x a x d

30^2=0^2+2 x a x 12

30x30=0+24a

900=24a

Divide both sides by 24

900/24=24a/24

37.5=a

Acceleration=37.5m/s^2

Force=mass x acceleration

Force=200 x 37.5

Force=7500

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