Answer:
P(red then blue) is [tex]\frac{15}{121}[/tex]
Step-by-step explanation:
Number of red marbles = 3
Number of white marbles = 3
Number of blue marbles = 5
Total number of marbles = 3+3+5=11
We are given that You return the first marble to the bag and then choose again.
We are supposed to find the P(red then blue).
Probability of drawing red marble = [tex]\frac{3}{11}[/tex]
You return the ball
So,Probability of drawing blue marble = [tex]\frac{5}{11}[/tex]
So,P(Red then blue)=[tex]\frac{3}{11} \times \frac{5}{11}=\frac{15}{121}[/tex]
Hence P(red then blue) is [tex]\frac{15}{121}[/tex]
