Answer:
The perimeter of the quadrilateral is 42 units
Step-by-step explanation:
Here, we have
For the line DC and DA are tangents to the circle then;
Distance from C to the point of contact with the circle along CD = Distance from C to the point of contact with the circle along CB = 4
Therefore;
Distance from D to the point of contact with the circle along DA is = Distance from D to the point of contact with the circle along DC = 9 - 4 = 5
Similarly, distance from A to the point of contact with the circle along AD = Distance from A to the point of contact with the circle along AB = 4
Therefore, distance from B to the point of contact with the circle along BA= 12 - 4 = 8 = Distance from B to the point of contact with the circle along BC
Hence, AB = 12
BC = 8 + 4 = 12
DC = 9
DA = 4 + 5 = 9
The perimeter of the quadrilateral = AB + BC + DC + DA = 12 + 12 + 9 + 9 = 42 units.
