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Chris is standing due south of a 20m flagpole at a point where the angle of elevation of the top of the pole is 35. Brandyn is standing due east of the flagpole at a point where the angle of elevation of the top of the pole is 27. How far is Brandyn from Chris?

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Answer:

Brandyn is 41.48m from Chris

Step-by-step explanation:

I have drawn an image depicting this question and I've attached it.

From the diagram, chris is standing at point B while Brandyn is at point D. x is the distance of brandyn to the bottom of the pole.

The height of the pole is AC.

Now, by trigonometric ratio, we can find AC. Thus;

AC/20 = tan 35

AC = 20 tan 35

AC = 14

Since,we now have AC, we can find x.

Similarly, 14/x = tan 27

x = 14 / tan 27

x = 27.48 m

Thus, total distance of brandyn from Chris = 14 + 27.48 = 41.48 m

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