the diagram shows a lawn with a fence along one edge
one can of weedkiller can cover 100 square metres
each can costs£19.75
work out the total cost of the cans of weedkiller needed to cover the lawn you must show some working

the diagram shows a lawn with a fence along one edgeone can of weedkiller can cover 100 square metreseach can costs1975work out the total cost of the cans of we class=

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Answer:

Step-by-step explanation:

The shape above is a trapezium, and the area of a trapezium can be calculated using

A = ½(a + b)h

Where, a and b is the two parallel line

Then, a = 12 and b = 20,

We need to find the height by applying Pythagoras theorem to triangle ABC

AC² = AB² + BC². Check attachment

a² = b² + c²

17² = 8² + h²

h² = 17² - 8²

h² = 289 - 64

h² = 225

h = √225

h = 15m

So, the area of the trapezium

A = ½(a + b)h

A = ½ × (12 + 20) × 15

A = ½ × 32 × 15

A = 16 × 15

A = 240m²

Given that, 100m² can be cover with one can

100m² = 1 can

100 m² = 1 can

240m² = x

Cross multiply

100 m² × x = 1 can × 240m²

divide both sides 100m²

x = 1 can × 240m² / 100m²

x = 2.4 can

So, we need 2.4 cans weed killer

Then, given that 1 can cost £19.75

1 can = £19.75

2.4 cans = 2.4 × £19.75

2.4 cans = £47.4

The cost of the weed killer is £47.4

Ver imagen Kazeemsodikisola

The shape of the area of the lawn that is to be treated with weedkiller is a

trapezoid.

The total cost of the cans of weedkiller needed to cover the lawn is £59.25

Reasons:

The given information are;

A rea covered by one can of weedkiller = 100 m²

The cost of each can = £19.75

The shape of the lawn = A trapezium

Required:

The cost of the cans of weedkiller needed to cover the lawn

Solution:

[tex]The \ area \ of \ the \ trapezoid = \dfrac{a + b}{2} \times h[/tex]

Where;

a = Top horizontal base = 12 m

b = Lower horizontal base = 20 m

h = The height = Length of the fence

Taking, the fence as being perpendicular to the 12 m, and 20 m sides, we have;

Translating the slant 17 m side, 12 m to the left, gives a right triangle, of

base length, l = 20 m - 12 m = 8 m

Therefore, by Pythagoras theorem;

Length of the fence, h = √(17² - 8²) = 15

h = 15 m

Which gives;

[tex]Area \ of \ the \ trapezoidal \ lawn = \dfrac{12 + 20}{2} \times 15 = 240[/tex]

The area of the trapezoidal lawn, A = 240 m²

Area per can, Cₐ = 100 m²/can

Therefore;

[tex]Number \ of \ cans \ required = \dfrac{A}{C_a} = \dfrac{240}{100} = 2.4[/tex]

The unit of weedkiller sold = 1 can per unit

Therefore;

Number of cans needed to be bought cover the lawn =  2 cans + 1 extra can, for the 0.4 more weedkiller needed

Which gives;

The number of cans of weedkiller to be bought = 3 cans of weedkiller

Total cost of the 3 cans of weedkiller = 3 × £19.75 = £59.25

The total cost of the cans of weedkiller needed to cover the lawn = £59.25

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