We have been given that Sarah invests her graduation money of $1,750 in an annuity that pays an interest rate of 6% compounded annually. We are asked to write an exponential function for her investment growth.
We will use compound interest formula to solve our given problem.
[tex]A=P(1+\frac{r}{n})^{nt}[/tex], where
A = Final amount after t years,
P = Principal amount,
r = Annual interest rate in decimal form,
n = Number of times interest is compounded per year,
t = Time in years.
[tex]6\%=\frac{6}{100}=0.06[/tex]
Since interest is compounded annually, so [tex]n=1[/tex].
[tex]f(t)=1750(1+\frac{0.06}{1})^{1\cdot t}[/tex]
[tex]f(t)=1750(1+0.06)^{ t}[/tex]
[tex]f(t)=1750(1.06)^{ t}[/tex]
Therefore, the function [tex]f(t)=1750(1.06)^{ t}[/tex] describes Sarah's investment growth.