Answer:
She should be expected to have 2.11 aces.
Step-by-step explanation:
I suppose there was a small typing mistake. It should be: On average she gets an ace of 8.44% of her serves.
Then
For each serve, there are only two possible outcomes. Either there is an ace, or there is not. The probability of there being an ace in a serve is independent of other serves. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
She gets an ace of 8.44% of her serves.
This means that [tex]p = 0.0844[/tex]
She attemps 25 serves:
This means that [tex]n = 25[/tex]
How many aces would you expect her to have
[tex]E(X) = np = 25*0.0844 = 2.11[/tex]
She should be expected to have 2.11 aces.
