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500.0 mL of gas at room temperature has a pressure of 19.0 psi. If the gas is placed in a 1.00L container and allowed to return to room temperature, what is its new pressure in psi? How many atm is this?

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drpelezo

Answer:

New Pressure in 1 Liter container = 9.5 psi = 0.646 atm

Explanation:

P₁ = 19 psi

V₁ = 500 ml = 0.500 Liter

P₂ = ?

V₂ = 1.00 L

Boyle's Law => P₁V₁ = P₂V₂

=> P₂ = P₂V₂/V₁ = (19psi)(0.500L)/(1.000L) = 9.5 psi x (0.068 atm/psi) = 0.646 atm