Respuesta :
Answer:B
Explanation:
elastic constant(k)=80N/m
extension(e)=0.1m
Elastic potential energy=(k x e^2)/2
Elastic potential energy=(80 x (0.1)^2)/2
Elastic potential energy=(80x0.1x0.1)/2
Elastic potential energy=0.8/2
Elastic potential energy=0.4
Elastic potential energy is 0.4 joules