there are only red, blue and green counters in a bag
there a 6 red counters
there are 4 blue counters
there are 8 green counters

matt takes a counter from a random bag
what is the probability that the counter is red?
give your answer as fraction

what is the probability that the counter is not blue?
give your answer as a fraction

Question

11-05-2020
Mathematics

contestada

there are only red, blue and green counters in a bag
there a 6 red counters
there are 4 blue counters
there are 8 green counters

matt takes a counter from a random bag
what is the probability that the counter is red?
give your answer as fraction

what is the probability that the counter is not blue?
give your answer as a fraction

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akiran007 akiran007 · Answer 1 · 2021-10-19T03:32:52+02:00

Probability is found out by dividing the favorable number of outcomes to the total number of outcomes.

The total number of counters are 6+ 4+8 = 18 marbles

The number of red counters are 6.

The probability of red = favorable outcome / total outcomes= 6/ 18

The total number of blue and green counters are 14 (excluding red).

The probability of not red = favorable outcome / total outcomes= 14/ 18

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facundo3141592 facundo3141592 · Answer 2 · 2021-10-21T13:56:20+02:00

We want to find the probabilities of randomly drawing different colors of counters from a bag.

The solutions are:

a) P = 1/3

b) P = 7/9

We know that in a bag there are:

6 red counters.
4 blue counters.
8 green counters.

For a total of 18 counters.

If all of these have the same probability of being randomly drawn, then the probability of taking a given color is equal to the quotient between the number of counters of that color and the total number of counters.

a) Probability of being red:

There are 6 red counters and 18 counters in total, so here the probability is:

p = 6/18 = 1/3

b) Probability of not being blue:

There are 14 not blue counters (6 red ones and 8 green ones) and 18 counters in total, so here the probability is:

p = 14/18 = 7/9

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