Given the equation representing a reaction:
3CuCl2(aq) + 2Al(s) — 3Cu(s) + 2AlCl3(aq)
The oxidation number of copper changes from
+1 to 0
+2 to 0
+2 to +1
4.
+6 to +3​

Respuesta :

Answer:

The answer is +2 to 0

Explanation:

I don't know why that is the answer but that's what the answer was on the same question on a quiz I just took so I hope this helps.

The oxidation number of copper changes from +2 to 0 in the given reaction.

What is oxidation state?

Oxidation state of any element tells about the gain or losses of the no. of electrons from that element.

Given chemical reaction is:

3CuCl₂(aq) + 2Al(s) → 3Cu(s) + 2AlCl₃(aq)

On the left side of the reaction, copper is in the +2 oxidation state because oxidation state of chlorine is -1. And on the right side of the reaction, copper is in zero oxidation state as it is present with no charge.

Hence, oxidation state of copper changes from +2 to 0.

To know more about oxidation state, visit the below link:

https://brainly.com/question/6498977