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Simplify.
Remove all perfect squares from inside the square root.
√63 =?

Respuesta :

pandaeyes1021

Answer:

[tex]3\sqrt{7}[/tex]

Step-by-step explanation:

Take 2 factors of 63 (the bigger the number the less you have to do):

                                                    [tex]\sqrt{63}[/tex]

                                                9             7

(The numbers 9 and 7 both multiply into 63)

So, now break it down even more since 9 is a perfect square:

                                                    [tex]\sqrt{63}[/tex]

                                                9             7

                                          3          3

Now that you have two 3's, you put that outside of the radical and keep the 7 inside:

[tex]3\sqrt{7}[/tex]

manissaha129

Answer:

[tex] \sqrt{63} =\sqrt{9\times7} = \sqrt{3 \times 3 \times 7} = 3 \sqrt{7} [/tex]

3√7 is the right answer.

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